Effectuer les calculs suivants :
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A = 4 × [3 + (2 - 1)]
A = 4 × [3 + (2 - 1)] = 4 × (3 + 1) = 4 × 4 = 16
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B = 3[6 - 4 + 2 × (2 + 1)]
B = 3[6 - 4 + 2 × (2 + 1)] = 3 × (6 - 4 + 2 × 3) = 3 × (6 - 4 + 6) = 3 × (2 + 6) = 3 × 8 = 24
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C = 4 × 5 × (2 + 3)
C = 4 × 5 × (2 + 3) = 4 × 5 × 5 = 20 × 5 = 100
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D = 3 + 4 × 5 - 1
D = 3 + 4 × 5 - 1 = 3 + 20 - 1 = 23 - 1 = 22
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E = (6 + 3) × 3 + [7 - (4 × 1 + 2)]
E = (6 + 3) × 3 + [7 - (4 × 1 + 2)] = 9 × 3 + [7 - (4 + 2)] = 27 + (7 - 6) = 27 + 1 = 28